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송동우님
2011.09.20 18:56
<?php
/////////////////// MySQL Information ////////////////////
$host = "localhost"; //MySQL Host
$user = "root"; // MySQL Username
$pass = ""; // MySQL Password
$database = ""; // Database name
$adminpassword = "jagcraft.tk"; //Administration Password
//////////////////////////////////////////////////////////
//////////////////// User Database ////////////////////////
$tablename = "accounts"; // Table name (the one that stores user account information)
$username = "username"; // Name of username column
$password = "password"; // Name of password column
$moneyname = "money"; // Name of money/currency column
$xAuth = false; // Are you using xAuth?
///////////////////////////////////////////////////////////
//////////////// InventorySQL Database ////////////////////
$InventorySQL = "InventorySQL"; //Your InventorySQL Table
$viewlimit = 15; //How many items per page
$bankname = "JagBank";
//Name of "Bank"
///////////////////////////////////////////////////////////
user
pass
database
adminpassword
여기까지는 mysql 및 db 설정일테고
tablename
username
password
moneyname
xauth
여기서 문제입니다 tablename 여기서 테이블을 설정하는거일텐데요
제 필드가
username , password 는 같은 테이블에 있는데
moneyname은 따른 필드에 있습니다.
moneyname을 어떻게 불러올수있죠????
/////////////////// MySQL Information ////////////////////
$host = "localhost"; //MySQL Host
$user = "root"; // MySQL Username
$pass = ""; // MySQL Password
$database = ""; // Database name
$adminpassword = "jagcraft.tk"; //Administration Password
//////////////////////////////////////////////////////////
//////////////////// User Database ////////////////////////
$tablename = "accounts"; // Table name (the one that stores user account information)
$username = "username"; // Name of username column
$password = "password"; // Name of password column
$moneyname = "money"; // Name of money/currency column
$xAuth = false; // Are you using xAuth?
///////////////////////////////////////////////////////////
//////////////// InventorySQL Database ////////////////////
$InventorySQL = "InventorySQL"; //Your InventorySQL Table
$viewlimit = 15; //How many items per page
$bankname = "JagBank";
//Name of "Bank"
///////////////////////////////////////////////////////////
hostuser
pass
database
adminpassword
여기까지는 mysql 및 db 설정일테고
tablename
username
password
moneyname
xauth
여기서 문제입니다 tablename 여기서 테이블을 설정하는거일텐데요
제 필드가
username , password 는 같은 테이블에 있는데
moneyname은 따른 필드에 있습니다.
moneyname을 어떻게 불러올수있죠????